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One edge of a painting is 6 in. longer than the other edge. The picture has a 2-inch-wide frame. Write a quadratic function f in standard form to represent the total area of the picture and frame. Then find the total area of the picture and the frame if its longer edge is 14 inches long.

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Answer:

One edge of a painting is 6 in. longer than the shorter edge. The picture has a 2-in.-wide frame. There is one rectangle inside the other rectangle. The distance between two edges of two rectangles is 2. The length of the rectangle is x + 6 and width is x. The portion between two rectangles is shaded. Part A Which quadratic function represents the total area of the picture and frame? A. f(x) = x2 + 8x + 12 B. f(x) = x2 + 10x + 24 C. f(x) = x2 + 12x + 32 D. f(x) = x2 + 14x + 40 Part B What is the total area of the %3D %3D framed picture if its shorter edge is 8 inches long? Enter your answer in the box. _in.2 x+ 6

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