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Evaluate ∫3x2sin(x3)cos(x3)dx by

(a) using the substitution u=sin(x3) and

(b) using the substitution u=cos(x3).

Explain why the answers from (a) and (b) are seemingly very different

Sagot :

ghanami

Answer:

Evaluate ∫3x2sin(x3)cos(x3)dx

Step-by-step explanation:

hello        (a) using the substitution u=sin(x3)  because

du =3x²(cos x3)dx

you have   ∫3x2sin(x3)cos(x3)dx = ∫udu=u²/2 +c............continu

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