Answered

At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Discover comprehensive answers to your questions from knowledgeable professionals on our user-friendly platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

A 19.5-mL sample of Ba(OH)2 is titrated with HCl. If 28.4 mL of 0.394 M HCl is needed to reach the endpoint, what is the concentration (M) of the Ba(OH)2 solution

Sagot :

asuwafohjames

The concentration of Ba(OH)₂ IS 0.287 M.

What is concentration?

This is the amount of solute in mol or in gram that will dissolve in 1 dm³ solution.

Equation of the reaction

  • Ba(OH)₂+2HCl→ BaCl₂+2H₂O

Formula:

  • CaVa/CbVb = Na/Nb................ Equation 1

Where:

  • Ca = Concentration of HCl
  • Va = Volume of HCl
  • Cb = Concentration of Ba(OH)₂
  • Vb = Volume of Ba(OH)₂
  • Na = number of moles of HCl
  • Nb = number of moles of Ba(OH)₂

Make Cb the subject of the equation

  • Cb = (CaVaNb)/(NaVb)................... Equation 2

From the equation and the question,

Given:

  • Ca = 0.394 M
  • Va = 28.4 mL
  • Vb = 19.5 mL
  • Na = 2
  • Nb = 1

Substitute these values into equation 2

  • Cb = (0.394×28.4×1)/(2×19.5)
  • Cb = 0.287 M.

Hence, The concentration of Ba(OH)₂ IS 0.287 M.

Learn more about concentration here: https://brainly.com/question/17206790


Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.