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Find cos(α) in the triangle.

Find Cosα In The Triangle class=

Sagot :

Answer:

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Ⲁⲛ⳽ⲱⲉⲅ:

[tex] \quad\hookrightarrow\quad \sf { \dfrac{35}{37} }[/tex]

Ⲋⲟⳑⳙⲧⳕⲟⲛ :

In the given triangle , for angle α , we have :

  • Base = 35
  • Hypotenuse = 37
  • Perpendicular = 12

And, cos α for a right angled triangle is the ratio of the adjacent side to the hypotenuse, where α is the acute angle ,i.e:

[tex] \quad\longrightarrow\quad {\pmb{\sf {cos\:\alpha = \dfrac{Base}{Hypotenuse} }}}[/tex]

Therefore:

[tex] \implies\quad \tt { cos\:\alpha = \dfrac{B}{H} }[/tex]

[tex] \implies\quad \tt\underline{ \underline{\pmb{{cos\:\alpha =\dfrac{35}{37}} }}}[/tex]