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I’ll give whoever answers 100 points and brainliest

Paul spends S100 on supplies to make T-shirts. He sells each T-shirt he makes for S12.
Which inequality can Paul use to determine how many T-shirts, 1, he needs to sell in order to make a profit?

A 12t - 100 < 0
B 12t + 100 > 0
C 12t - 100 > 0
D 12t + 100 < 0

A
B
C
D



Sagot :

Answer:

Therefore he can use inequality C because profit cannot be in less than and should be with greater than.

Step-by-step explanation:

A

[tex]\sf \hookrightarrow 12t - 100 < 0[/tex]

[tex]\sf \hookrightarrow 12t < 100[/tex]

[tex]\sf \hookrightarrow t < \frac{100}{12}[/tex]

[tex]\sf \hookrightarrow t < \frac{25}{3}[/tex]

B

[tex]\sf \hookrightarrow 12t + 100 > 0[/tex]

[tex]\sf \hookrightarrow 12t < -100[/tex]

[tex]\sf \hookrightarrow t > -\frac{100}{12}[/tex]

[tex]\sf \hookrightarrow t > -\frac{25}{3}[/tex]

C

[tex]\sf \hookrightarrow 12t - 100 > 0[/tex]

[tex]\sf \hookrightarrow 12t > 100[/tex]

[tex]\sf \hookrightarrow t > \frac{100}{12}[/tex]

[tex]\sf \hookrightarrow t > \frac{25}{3}[/tex]

D

[tex]\sf \hookrightarrow 12t + 100 < 0[/tex]

[tex]\sf \hookrightarrow 12t < -100[/tex]

[tex]\sf \hookrightarrow t < \frac{ -100}{12}[/tex]

[tex]\sf \hookrightarrow t < -\frac{25}{3}[/tex]

Answer:

C)  12t - 100 > 0

Step-by-step explanation:

Let t = number of t-shirts sold

He will need to subtract the supply cost ($100) from the selling price of the t-shirts.  The final amount will need to be greater than zero for it to be profit.

12t - 100 > 0

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