Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Join our Q&A platform to get precise answers from experts in diverse fields and enhance your understanding. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

help pleaseeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Help Pleaseeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee class=

Sagot :

nova66

Answer:

-31>v

Step-by-step explanation:

look above there

hope it helps

View image nova66

Hello.

The first step is to subtract 14 from both sides:

[tex]\mathrm{33-14 > \frac{v}{3} +14-14}[/tex]

[tex]\mathrm{33-14 > \frac{v}{3} }[/tex]

[tex]\mathrm{19 > \frac{v}{3} }[/tex]

Now, multiply both sides by 3 in order to get rid of the fraction:

[tex]\mathrm{19*3 > \frac{v}{3} *3}[/tex]

[tex]\mathrm{57 > v}[/tex]

Since 57 is greater than v, v is less than 57:

[tex]\mathrm{v < 57}[/tex]

Therefore, your answer is

[tex]\mathrm{v < 57}[/tex]

I hope this helps.

Have a nice day.

[tex]\boxed{imperturbability}[/tex]

Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.