Answered

Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Discover in-depth solutions to your questions from a wide range of experts on our user-friendly Q&A platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

The length of a rectangle is 3 less than 2 times its width. The area of the rectangle is 77 squared feet.

1. The width of the rectangle is .

2. The length of the rectangle is .

Sagot :

princeburg4

Answer:

Let the Width(W) =X feet

then Length(L) = (2X-3)feet

Area of the rectangle (A)=77 square feet

A = L× W

L×W=A

(2X-3) × X = 77

2X²- 3X =77

2X²-3X -77=0

Solving it using the factorization method

2X²-14X+11X-77=0

(2X²-14X)+(11X-77)=0

2X(X-7) + 11(X-7)=0

(2X+11)(X-7) =0

When 2X+11=0

X= -11/2

When X-7=0

X = 7

Therefore X= 7

Width = X feet

= 7feet

The width is 7feet

Length = (2X-3)feet

= (2×7) -3)feet

=(14-3)feet

=11feet

We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.