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The sum of the ages of Bailey and Celine is x years. If Celine is 8 years older than Bailey, how many years old will Celine be x years from now, in terms of x

Sagot :

Step-by-step explanation:

b = age of Bailey

c = age of Celine

b + c = x

c = b + 8

so, using that identity in the first equation

b + b + 8 = x

2b + 8 = x

or, to go "after" c (Celine) :

b = c - 8

c - 8 + c = x

2c - 8 = x

2c = x + 8

c = (x + 8)/2

in x years c will have increased to c+x, and b to b+x.

so,

b + x + c + x = x + 2x = 3x

and

2c - 8 = 3x

2c = 3x + 8

c = (3x + 8)/2

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