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If a compound is found to contain 24.78% Carbon, 2.08% Hydrogen, and 73.14% Chlorine the empirical formula would be

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Eduard22sly

The empirical formula of the compound containing 24.78% Carbon, 2.08% Hydrogen, and 73.14% Chlorine is CHCl

Data obtained from the question

  • Carbon (C) = 24.78%
  • Hydrogen (H) = 2.08%
  • Chlorine (Cl) = 73.14%
  • Empirical formula =?

How to determine the empirical formula

The empirical formula of the compound can be obtained as illustrated below:

Divide by their molar mass

C = 24.78 / 12 = 2.065

H = 2.08 / 1 = 2.08

Cl = 73.14 / 35.5 = 2.06

Divide by the smallest

C = 2.065 / 2.06 = 1

H = 2.08 / 2.06 = 1

Cl = 2.06 / 2.06 = 1

Thus, the empirical formula of the compound is CHCl

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