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The mean of a set of credit scores is Mu = 690 and Sigma = 14. Which statement must be true about z694? z694 is within 1 standard deviation of the mean. Z694 is between 1 and 2 standard deviations of the mean. Z694 is between 2 and 3 standard deviations of the mean. Z694 is more than 3 standard deviations of the mean.

Sagot :

satpreetkaur2005

Answer: the correct answer is b!

Step-by-step explanation: hope this helped :)

Using the normal distribution, it is found that the correct statement is:

694 is within 1 standard deviation of the mean.

Normal Probability Distribution

In a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

As stated in this problem, [tex]\mu = 690, \sigma = 14[/tex]. For X = 694, the z-score is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{694 - 690}{14}[/tex]

[tex]Z = 0.286[/tex]

Since |Z| < 1, 694 is within 1 standard deviation of the mean.

More can be learned about the normal distribution at https://brainly.com/question/24663213

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