Find the best solutions to your questions at Westonci.ca, the premier Q&A platform with a community of knowledgeable experts. Experience the ease of finding reliable answers to your questions from a vast community of knowledgeable experts. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
The equilibrium constant has been the ratio of the product and the reactant concentration raised to the stoichiometric coefficient. The equilibrium concentration of methane is 0.059 M.
What is equilibrium?
The equilibrium can be defined as the condition in which the rate of formation of product and the rate of breakdown of product is equal.
The given reaction has been:
[tex]\rm CO+3\;H_2\;\leftrightharpoons\;CH_4+H_2O[/tex]
The equilibrium constant (kc) for the reaction has been given as :
[tex]k_c=\rm \dfrac{[CH_4][H_2O]}{[CO][H_2]^3}[/tex]
Substituting the values of the equilibrium concentration in the equation as:
[tex]k_c=\dfrac{[\text C\text H_4][0.020]}{[0.30][0.10]^3} \\\\3.90=\dfrac{[\text C\text H_4]\;\times\;0.020}{0.0003} \\\\\rm CH_4=0.059\;M[/tex]
The equilibrium concentration of methane is 0.059 M. Thus, option C is correct.
Learn more about equilibrium concentration, here:
https://brainly.com/question/7949757
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.