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Sagot :
Answer:
Joe's age = 25 years
Mary's age = 50 years
Bob's age = 10 years
Step-by-step explanation:
Joe's age = x years
Mary's age = 2*x = 2x
Bob's age = x - 15
Sum of their ages = 85
x + 2x + x - 15 = 85
Combine like terms,
4x - 15 = 85
Add 15 to both sides
4x - 15 + 15 = 85 + 15
4x = 100
Divide both sides by 4
x = 100/4
x = 25
Joe's age = 25 years
Mary's age = 2*25 = 50 years
Bob's age = 25 - 15 = 10 years
Let Joe's age be x
Let Bob's age be x-15
Let Mary's age be 2x
Now,
[tex] \mathcal{Bob's \: age+ Joe's \: age+ Mary's \: age = 85}[/tex]
Substitute the values we just gave ATQ
[tex] \sf \: x - 15 + x + 2x = 85 \\ \sf \: 4x - 15 = 85 \\ \sf \: 4x = 85 + 15 \\ \sf \: 4x = 100 \\ \sf \: x = 25[/tex]
Find their ages with the help of value of x we just found!~
[tex]\large{|\underline{\mathtt{\red{b}\blue{o}\orange{b}\pink{'}\blue{ s }\purple{ \: }\green{a}\red{g}\blue{e}\purple{ \searrow}}}}[/tex]
[tex] \tt \: x - 15 \\ \tt \: 25 - 15 \\ \colorbox{lightyellow}{\bf \: = 10}[/tex]
[tex]\large{|\underline{\mathtt{\red{j}\blue{o}\orange{e}\pink{'}\blue{ s }\purple{ \: }\green{a}\red{g}\blue{e}\purple{ \searrow}}}}[/tex]
[tex] \tt \: x \\ \colorbox{lightyellow}{\bf \: = 25}[/tex]
[tex]\large{|\underline{\mathtt{\red{m}\blue{a}\orange{r} \green{y}\pink{'}\blue{ s }\purple{ \: }\green{a}\red{g}\blue{e}\purple{ \searrow}}}}[/tex]
[tex] \tt \: 2x \\ \tt \: 2 \times 25 \\ \colorbox{lightyellow}{\bf \: = 50}[/tex]
Therefore,
- Bob's age = 10
- Joe's age = 25
- Mary's age = 50
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