Gotenks99
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For the following reaction, 3.07 grams of sulfur dioxide are mixed with excess water. The reaction yields 2.84 grams of sulfurous acid (H₂SO3).

sulfur dioxide (g) + water (L)→ sulfurous acid (H₂SO3) (g)

What is the theoretical yield of sulfurous acid (H₂SO3)? 3.93grams

What is the percent yield for this reaction?72.2%​

For The Following Reaction 307 Grams Of Sulfur Dioxide Are Mixed With Excess Water The Reaction Yields 284 Grams Of Sulfurous Acid HSO3sulfur Dioxide G Water L class=

Sagot :

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3.93 and 72.2%

Explanation:

Theoretical Yield:

[tex]3.07 \: g \: SO₂ \times \frac{1 \: mol \: SO₂}{64.07g \: SO₂} \times \frac{1 \: mol \: H₂SO₃}{1 \: mol \: SO₂} \times \frac{82.09 \: g \: H₂SO₃}{1 \: mol \:H₂SO₃ } = 3.933 \: g \: H₂SO₃[/tex]

Percent Yield:

[tex] \frac{2.84 \: g}{3.993 \: g} \times 100 = 72.2\%[/tex]

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