Ⲁⲛ⳽ⲱⲉⲅ:
[tex] \quad\hookrightarrow\quad \sf {5,790,806.5\:ft^3 }[/tex]
Ⲋⲟⳑⳙⲧⳕⲟⲛ:
Here, we area provided a cone with:
- Radius = 48m
- Height = 68 m
We have to find the volume of the cone in feet³, and we are given that 1m = 3.2808ft
Ⳙ⳽ⲓⲛⳋ ⳨ⲟⲅⲙⳙⳑɑ:
The volume of a cone is equal to one third of the volume of a cylinder having the same base radius and height ,i.e:
[tex] \quad\longrightarrow\quad \sf { V =\dfrac{1}{3}\pi r^2 h }[/tex]
Therefore, Volume:
[tex] \implies\quad \tt {V = \dfrac{1}{3}\pi r^2 h }[/tex]
[tex] \implies\quad \tt { V =\dfrac{1}{3}\times 3.14 \times 48^2 \times 68 }[/tex]
[tex] \implies\quad \tt { V =\dfrac{1}{\cancel{3}}\times 3.14\times \cancel{2304} \times 68}[/tex]
[tex] \implies\quad \tt {V =3.14\times 768\times 68 }[/tex]
[tex] \implies\quad \tt {V = 163,983.36}[/tex]
[tex] \implies\quad \tt { V = 163,983.36 \times (3.2808)^3 \qquad\quad\bigg[ As, \: 1m = 3.2808ft\bigg]}[/tex]
[tex] \implies\quad \tt {V = 163,983.36\times 35.30 }[/tex]
[tex] \implies\quad\underline{\pmb{ \tt { V = 5,790,806.5 ft^3}}}[/tex]
ㅤㅤㅤ~Hence, the volume of given cone is 5,790,806.5 ft³.
