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The height of a parallelogram is 10 feet more than its base. If the area of the parallelogram is 1200 square feet, find its base and height.​

Sagot :

The base is 30cm & height is 40cm

Step-by-step explanation:

Height is 10+ the base

H is (x + 10)

B is x

(x is a variable - representing an unknown number)

A= bxh

1200 = x x (x+10)

(expand brackets)

1200 = x^2 + 10x

- 1200 (both side)

Now we've got to factorise to find the value of x :

x^2 + 10x - 1200 = 0

x to get - 1200

+ to get 10

40 x - 30= - 1200

40 + - 30 = 10

Slipt 10x into 40x & - 30x, then, factorise:

x^2 + 10x - 1200

x^2 + 40x - 30x - 1200

x(x + 40). - 30 (x + 40)

(x - 30)(x+40) =0

(x-30) =0

+30

x = 30

(x+40) =0

-40

x = - 40

Thus, x is going to be 30 because we can't have a negative length (I.e., - 40.)

So, the base is 30cm & height is 40cm

(30+10, giving them a difference of 10cm)

Check:

A= bxh

= x x (x+10)

= 30 x (30+10)

= 30 x (40)

= 1200 (square feet)

Hope this helps!