Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Get quick and reliable solutions to your questions from a community of experienced experts on our platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
The base is 30cm & height is 40cm
Step-by-step explanation:
Height is 10+ the base
H is (x + 10)
B is x
(x is a variable - representing an unknown number)
A= bxh
1200 = x x (x+10)
(expand brackets)
1200 = x^2 + 10x
- 1200 (both side)
Now we've got to factorise to find the value of x :
x^2 + 10x - 1200 = 0
x to get - 1200
+ to get 10
40 x - 30= - 1200
40 + - 30 = 10
Slipt 10x into 40x & - 30x, then, factorise:
x^2 + 10x - 1200
x^2 + 40x - 30x - 1200
x(x + 40). - 30 (x + 40)
(x - 30)(x+40) =0
(x-30) =0
+30
x = 30
(x+40) =0
-40
x = - 40
Thus, x is going to be 30 because we can't have a negative length (I.e., - 40.)
So, the base is 30cm & height is 40cm
(30+10, giving them a difference of 10cm)
Check:
A= bxh
= x x (x+10)
= 30 x (30+10)
= 30 x (40)
= 1200 (square feet)
Hope this helps!
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.