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Answered

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twice the square of an integer added to 6 is 12 times larger than the integer, form qn equation​

Sagot :

Integer be x

[tex]\\ \rm\rightarrowtail 2x^2+6=12x[/tex]

[tex]\\ \rm\rightarrowtail 2x^2-12x+6=0[/tex]

Equation is

[tex]\\ \rm\rightarrowtail x^2-6x+3=0[/tex]

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