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A student dissolves 0.250 mol NaC1 in 2.05 kg H20. What is the molality of the resulting solution? Show your work.

Sagot :

[tex]\boxed{\sf Molality=\dfrac{Moles\:of\:solute}{Mass\:of\: solvent\:in\;kg}}[/tex]

  • Moles=0.25
  • Mass=2.5kg

[tex]\\ \rm\Rrightarrow Molality=\dfrac{0.25}{2.5}=0.1m[/tex]

laceyward

Answer:

the person below me is wrong

Explanation:

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