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Sagot :
The number of moles of iron (III) oxide contained in 2.5 kg of rust is 15.625 moles.
What is a mole?
A mole is the mass of a substance that contains 6.023×10²³ particles of that substance.
To calculate the number of moles of iron (III) Oxide contained in 2.5 kg of the rust, we use the formula below.
Formula:
- n = R.m/m.m................. Equation 1
Where:
- n = number of mole of iron (III) oxide
- R.m = mass of iron (III) oxide that is involved in the reaction (rusting)
- m.m = molar mass of iron (III) oxide.
From the question,
Given:
- R.m = 2.5 kg = 2500 g
- m.m of Fe₂O₃ = [(2×56)+(3×16)] = (112+48) = 160 g/mol
Substitute these values into equation 1
- n = 2500/160
- n = 15.625 moles.
Hence, The number of moles of iron (III) oxide contained in 2.5 kg of rust is 15.625 moles.
Learn more about moles here: https://brainly.com/question/15356425
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