Discover the answers you need at Westonci.ca, where experts provide clear and concise information on various topics. Connect with a community of experts ready to help you find solutions to your questions quickly and accurately. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
Answer:
x = 4[tex]\sqrt{5}[/tex]
Step-by-step explanation:
Using Pythagoras' identity in the right triangle.
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
x² + 1² = 9²
x² + 1 = 81 ( subtract 1 from both sides )
x² = 80 ( take square root of both sides )
x = [tex]\sqrt{80}[/tex] = [tex]\sqrt{16(5)}[/tex] = [tex]\sqrt{16}[/tex] × [tex]\sqrt{5}[/tex] = 4[tex]\sqrt{5}[/tex]
Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.