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Please help fast! C=?

Please Help Fast C class=

Sagot :

Answer:

Step-by-step explanation:

By the law of Sines,

[tex]\frac{\sin 88^{\circ}}{26}=\frac{\sin C}{21}\\\sin C=\frac{21 \sin 88^{\circ}}{26}\\C=\sin^{-1} \left(\frac{21 \sin 88^{\circ}}{26} \right) \approx 54^{\circ}[/tex]

However, it follows that [tex]C \approx 126^{\circ}[/tex] must also be a solution.

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