Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

Kaylee needed to write the equation of an exponential function from points on the graph of the function. To determine the value of b, Kaylee chose the ordered pairs (1, 6) and (3, 48) and divided 48 by 6. She determined that the value of b was 8. What error did Kaylee make? Complete the explanation.


Kaylee Needed To Write The Equation Of An Exponential Function From Points On The Graph Of The Function To Determine The Value Of B Kaylee Chose The Ordered Pai class=

Sagot :

Answer:

  • 1

Step-by-step explanation:

The exponent function is:

  • f(x) = a*bˣ

You can find the value of b if you divide the consecutive values of f(x).

  • f(x + 1) = a*bˣ⁺¹
  • f(x + 1)/f(x) = a*bˣ⁺¹/a*bˣ = bˣ⁺¹⁻ˣ = b

The missing number in the explanation is 1.

Kaylee gets:

  • f(3) / f(1) = 48/6 = 8 but it is the value of b² not b.

Answer:

One

Step-by-step explanation:

General form of an exponential function: [tex]y=ab^x[/tex]

where a is the initial value, b is the growth/decay factor, and x is the independent variable

If b > 1 the function will grow (increase).  If 0 < b < 1 then the function will decay (decrease)

The value Kaylee found is not the constant ratio of successive values.  She should use ordered pairs with x-values that differ by 1

This is how Kaylee computed the value of b, which was incorrect as the solution of 8 is for [tex]b^2[/tex]:

at (1, 6):   [tex]ab^1=6[/tex]

at (3, 48)  [tex]ab^3=48[/tex]

[tex]\implies \dfrac{ab^3}{ab^1}=\dfrac{48}{6}\\\\\implies b^2=8\\\\\implies b=\pm\sqrt{8} =2\sqrt{2}[/tex]

(b is positive since the function is increasing)

However, if Kaylee used the ordered pairs with a difference of one, e.g.  x = 1 and x = 2, then she would have computed the correct value of b:

at (1, 6):   [tex]ab^1=6[/tex]

at x = 2:  [tex]ab^2=y[/tex]

[tex]\implies \dfrac{ab^2}{ab^1}=\dfrac{y}{6}\\\\\implies b=\dfrac{y}{6}[/tex]

Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.