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What is an equation of the line that passes through the points (3, 2) and (6, -3)?

Sagot :

Answer:

y=-5/3x+7

Step-by-step explanation:

-3-2/6-3= -5/3 (slope)

y=-5/3x+b

2=-5+b

b=7

y=-5/3x+7

Answer:

[tex]y=-\frac{5}{3} x+7[/tex]

Step-by-step explanation:

Calculate the slope from 2 points.

[tex]\frac{y_{2} - y_{1}}{x_{2} - x_{1}}[/tex]

[tex]\frac{-3 - 2}{6 - 3}[/tex]

[tex]\frac{-5}{3}[/tex]

Substitute the slope (m) in the slope-intercept form of the equation.

[tex]y=-\frac{5}{3} x[/tex]

Solve for b, which is the y-intercept of the line. Plot the line and move it to fit the points.

[tex]y = 7[/tex]

Substitute b, into the equation.

[tex]y=-\frac{5}{3} x+7[/tex]

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