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Sagot :

linandrew41

[tex]\frac{5(u^{-3})^2}{2u^8} =\frac{5u^{-6} }{2u^8} = \frac{5}{2} u^{-6-8} =\frac{5}{2} u^{-14} =\frac{5}{2u^{14} }[/tex]

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