At Westonci.ca, we provide reliable answers to your questions from a community of experts. Start exploring today! Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
Answer:
we know that
area of the circle is equal to
A=pi* r^{2}A=pi∗r
2
solve for r
r= \sqrt{ \frac{A}{pi}}r=
pi
A
for A=60 cm^{2}60cm
2
r= \sqrt{ \frac{60}{pi}} cmr=
pi
60
cm
we know that
\begin{gathered} \sqrt{60} = \sqrt{ 2^{4}*3*5} \\ =2 \sqrt{15} \end{gathered}
60
=
2
4
∗3∗5
=2
15
so
\sqrt{ \frac{60}{pi}}=2 \sqrt{ \frac{15}{pi}}
pi
60
=2
pi
15
2 \sqrt{ \frac{15}{pi}}=2 \frac{ \sqrt{15}}{ \sqrt{pi}} * \frac{ \sqrt{pi}}{ \sqrt{pi}}2
pi
15
=2
pi
15
∗
pi
pi
=2 \frac{ \sqrt{15pi}}{pi} cm=2
pi
15pi
cm
the answer is
2 \frac{ \sqrt{15pi}}{pi} cm2
pi
15pi
cm
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.