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Answered

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PLEASE HELP ME RN!!!!!

PLEASE HELP ME RN class=

Sagot :

fieryanswererft

Answer:

32,  2√7

Explanation:

given: [tex]\sf \bold x^2+6x+2=0[/tex]

using quadratic formula:   [tex]\boxed{\boxed{\sf x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a}}}[/tex]

solve using the equation:

  • [tex]\sf x_{1,\:2}=\dfrac{-6\pm \sqrt{6^2-4\cdot \:1\cdot \:2}}{2\cdot \:1}[/tex]

  • [tex]\sf x_1=\dfrac{-6+2\sqrt{7}}{2\cdot \:1},\:x_2=\dfrac{-6-2\sqrt{7}}{2\cdot \:1}[/tex]

  • [tex]\sf x=-3+\sqrt{7},\:x=-3-\sqrt{7}[/tex]

given a > β

  • so -3+√7 > -3-√7
  • a =  -3+√7 and β = -3-√7

solve:

  • (-3+√7)² + ( -3-√7)²
  • 32

and

  • -3+√7  - -3-√7
  • 2√7
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