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A 0.250-kg rock is thrown straight up, accelerated by an average upward net force of 242 N that acted on it while it moved 32.0 cm upward. Ignore friction or air resistance. How much net work was done to accelerate the rock to its launch speed? What maximum height above the launch point will the rock reach?​

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(a) The work done on the rock by upward net force is 77.44 J.

(b) The maximum height reached by the block is 31.61 m.

Work done to accelerate the rock to the given height

The work done on the rock is calculated as follows;

W = Fd

W = 242 x 0.32

W = 77.44 J

Maximum height reached by the rock from the launch point

The maximum height reached by the block is calculated as follows;

W = mgh

77.44 = 0.25 x 9.8 x h

h = (77.44)/(2.45)

h = 31.61 m

Learn more about work done here: https://brainly.com/question/8119756

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