Answered

Get the answers you need at Westonci.ca, where our expert community is dedicated to providing you with accurate information. Join our platform to connect with experts ready to provide precise answers to your questions in different areas. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

[tex]\boxed{\large{\sf Hello\: Brainlians}}[/tex]


Find the derivative of the below function using first principle

[tex]\\ \rm\rightarrowtail f(x)=\sqrt{sinx}[/tex]

Note:-

Spams/irrelevant/incomplete/copied /wrong answers will be deleted on the spot.



Don't add incomplete answer ,solve with proper explanation and all steps .


​

Sagot :

Nepalieducation

Answer:

[tex]\frac{cosx}{2\sqrt{sinx} }[/tex]

Step-by-step explanation:

The answer is in the attachment,

View image Nepalieducation
View image Nepalieducation
Baraq

From the definition,

f¹ (x) = Lin f(x+h) - f(x)

Solution

f(x) =√sinx

f¹(x) = f(x+h) - f(x) \ h

√sin (x+h) - √sinx\h

let,

sin (x+h) = u+k

f sin x = u

k = (u+k) - u........i

= sin(x+h) - sin x........ii

h......0 = k......0...........iii

√u+k -√u\h

√u+k-√u\x. • k\h

√u+k-√u\k sin (x+h) - sinx\h

{(√u+k)²-(√u)²\k√u+k+√u}

2cos(x+h/2) sin (h/2)\h

1\√u+√u • 1 cos(x+0)

¹/2√u cos x

¹/2√sinx cos x (u= sin x)

f¹(x) = cos x/2√sinx

Therefore, the answer is cos x/2√sinx.

learn more about fraction: https://brainly.com/question/78672

Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.