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Quadrilateral ABCD is a rectangle. If m /_DBC = 10x and m /_ACB = 4x^2-6, find m /_ACB​

Quadrilateral ABCD Is A Rectangle If M DBC 10x And M ACB 4x26 Find M ACB class=

Sagot :

gangumin696

Answer:

5

Step-by-step explanation:

m∠DBC = m∠ACB

4[tex]x^{2}[/tex]-6=10x

4[tex]x^{2}[/tex]-10x-6=0

(4x-2)(x+3)=0

x = [tex]\frac{1}{2}[/tex] or -3

The angle can't be negative.

∴ x = [tex]\frac{1}{2}[/tex]

m∠ACB = 4[tex]x^{2}[/tex] = 10x = 10 X [tex]\frac{1}{2}[/tex]= 5

I hope it helps you!

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