nicolliasimao
Answered

Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Connect with a community of experts ready to help you find solutions to your questions quickly and accurately. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

The Graph above shows the speed of a car traveling in a straight line as a function of time. The car accelerates uniformly and reaches a speed Vb of 4.00 m/s in 8.00 seconds. Calculate the distance traveled by the car from a time of 2.00 to 5.90 seconds.

Sagot :

Answer:

Where is the graph??

If a car travels from zero to 4 m/s ins 8 sec

a = 4 / 8 = .5 m/s^2

V (2) = 2 * .5 = 1 m/s after 2 sec

S = V t + 1/2 a t^2

S = 1 * 3.9 + 1/2 * 1/2 *3.9^2 = 3.9 + 3.80 = 7.70 m   from 2 to 5.9  sec

Check:

Total distance traveled = 1/2 a t^2 = 5.9^2 / 4 = 8.70 m

Distance traveled in 2 sec = 1/2 * 1/2 * 4 = 1 m

Total distance from 2 to 5.9 = 8.7 - 1 = 7.7 m agreeing with thw above

We appreciate your time. Please come back anytime for the latest information and answers to your questions. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.