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Sagot :

Answer:

-2

Step-by-step explanation:

Apply the difference of two squares formula:

[tex]\displaystyle \large{(a-b)(a+b) = a^2-b^2}[/tex]

Therefore:

[tex]\displaystyle \large{(3-\sqrt{11})(3+\sqrt{11}) = 3^2-(\sqrt{11})^2}\\\displaystyle \large{(3-\sqrt{11})(3+\sqrt{11}) = 9-11}\\\displaystyle \large{(3-\sqrt{11})(3+\sqrt{11}) = -2}[/tex]

Therefore, -2 is the final answer.

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Summary

  • Difference of Two Squares

[tex]\displaystyle \large{(a-b)(a+b)=a^2-b^2}[/tex]

  • Squared Surd

[tex]\displaystyle \large{(\sqrt{a})^2 = a}[/tex]

[tex](3 - \sqrt{11} )(3 + \sqrt{11} )[/tex]

Use the identity (a-b)(a+b)=a²-b²

  • a = 3
  • b = √11

[tex] {3}^{2} - { \sqrt{11 }^{2} }[/tex]

[tex]9 - 11[/tex]

[tex] - 2[/tex]

Thus, Option A is the correct choice!!~