Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
Answer:
[tex]
[tex] \large{\boxed{\sf Hypotenuse = 16.97\ cm }}[/tex]
Hypotenuse=16.97 cm
Step-by-step explanation:
Here it is given that the area of a right isosceles ∆ is 72 cm² . Let us assume that each equal side is x . Therefore the height and the base of the ∆ will be same that is x .
p
[tex] \begin{gathered}\sf\qquad\longrightarrow [/tex]
Area =\dfrac{1}{2}(base)(height)\\\end{gathered}⟶Area=21(base)(height)
[tex] \begin{gathered}\sf\qquad\longrightarrow[/tex]
[tex] 72cm^2=\dfrac{1}{2}(x)(x)\\\end{gathered} [/tex]
⟶72cm2=21(x)(x)
[tex] \begin{gathered}\sf\qquad\longrightarrow x^2=[/tex]
144cm^2\\\end{gathered}⟶x2=144cm2
[tex] \begin{gathered}\sf\qquad\longrightarrow x[/tex]
[tex] =\sqrt{144cm^2}\\\end{gathered}⟶x=144cm2 [/tex]
[tex]\sf\qquad\longrightarrow \pink{x = 12cm }⟶x=12cm [/tex]
Hence we may find hypotenuse using Pythagoras Theorem as ,
[tex] \sf\qquad\longrightarrow h =\sqrt{ p^2+b^2}⟶h=p2+b2 [/tex]
Here p = b = 12cm ,
[tex] \begin{gathered}\sf\qquad\longrightarrow h =\sqrt{ (12cm)^2+(12cm)^2}\\\end{gathered} [/tex]
⟶h=(12cm)2+(12cm)2
[tex] \begin{gathered}\sf\qquad\longrightarrow h [/tex]
[tex] =\sqrt{144cm^2+144cm^2}\\\end{gathered}[/tex]
⟶h=144cm2+144cm2
[tex] \begin{gathered}\sf\qquad\longrightarrow h[/tex]
=\sqrt{288cm^2}\\\end{gathered}⟶h=288cm2
[tex] \sf\qquad\longrightarrow \pink{ hypotenuse=[/tex]
16.97cm }⟶hypotenuse=16.97cm
Hence the hypotenuse is 16.97 cm .
[/tex]
Answer:
$864
Step-by-step explanation:
100-10 = 90/100= 0.9 (multiplier)
1200*0.9= 1080
100-20 = 80/100= 0.8 (2nd multiplier)
1080*0.8= 864
hope this helps
We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.
