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What is the equation of the line that is perpendicular to line m and passes through the point (3,2)

What Is The Equation Of The Line That Is Perpendicular To Line M And Passes Through The Point 32 class=

Sagot :

Answer:

y= 2/5x+4/5

Step-by-step explanation:

identify two points on line m then find it's gradient.

using the gradient of line m find the gradient of the perpendicular line

then use points (3,2) and (x,y) to find it's equation.

Answer:

y = [tex]\frac{2}{5}[/tex] x + [tex]\frac{4}{5}[/tex]

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (- 2, 2) and (x₂, y₂ ) = (0, - 3) ← 2 points on the line

m = [tex]\frac{-3-2}{0-(-2)}[/tex] = [tex]\frac{-5}{0+2}[/tex] = - [tex]\frac{5}{2}[/tex]

given a line with slope m then the slope of a line perpendicular to it is

[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{-\frac{5}{2} }[/tex] = [tex]\frac{2}{5}[/tex] , then

y = [tex]\frac{2}{5}[/tex] x + c ← is the partial equation

to find c substitute (3, 2 ) into the partial equation

2 = [tex]\frac{6}{5}[/tex] + c ⇒ c = 2 - [tex]\frac{6}{5}[/tex] = [tex]\frac{10}{5}[/tex] - [tex]\frac{6}{5}[/tex] = [tex]\frac{4}{5}[/tex]

y = [tex]\frac{2}{5}[/tex] x + [tex]\frac{4}{5}[/tex] ←  equation of perpendicular line

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