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A rectangular dog cage has a length of 4½ feet and a width of 3 ¾ feet. What is the area of the cage?

Sagot :

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Answer:

  • 16.875 feet²

Solution:

We are given that :

  • Length of rectangular dog cage = [tex]\sf 4\dfrac{1}{2} [/tex] feet.
  • Width of rectangular dog cage = [tex]\sf 3\dfrac{3}{4} [/tex] feet.

Area of the cage:

  • ➙ Length × width

Therefore,

[tex] \implies\quad \tt {A = Length \times Width}[/tex]

[tex] \implies\quad \tt {A = 4\dfrac{1}{2}\times 3\dfrac{3}{4} }[/tex]

[tex] \implies\quad \tt { A =\dfrac{(4\times 2)+1}{2}\times \dfrac{(3\times 4)+3}{4}}[/tex]

[tex] \implies\quad \tt {A =\dfrac{8+1}{2}\times \dfrac{12+3}{4} }[/tex]

[tex] \implies\quad \tt { A =\dfrac{9}{2}\times \dfrac{15}{4}}[/tex]

[tex] \implies\quad \tt { A = \dfrac{135}{8}}[/tex]

[tex] \implies\quad \underline{\underline{\pmb{\tt {A = 16.875}} }}[/tex]

SupremeStrange

Step-by-step explanation:

Given :-

  • Length :- 4½ feet
  • Width :- 3¾ feet

To find :-

  • Area of rectangular dog cage

Solution :-

Area of rectangular dog cage :- l×w

putting the values,

[tex]3 \frac{3}{4} \times 4 \frac{1}{2} [/tex]

[tex] \frac{15}{4} \times \frac{9}{2} [/tex]

Area = 135/8 feet²

Area = 16.875 ft²

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