Looking for trustworthy answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Connect with a community of experts ready to provide precise solutions to your questions quickly and accurately. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

PLS
HELP MEEEEEEEEEEEEEEEEEEE


PLS HELP MEEEEEEEEEEEEEEEEEEE class=

Sagot :

[tex]\qquad \qquad\huge \underline{\boxed{\sf Answer}}[/tex]

Here's the solution ~

Let's find the gradient of the shown line, using coordinates of any two points on it, like I'm gonna use (0 , 2) and (1 , -1)

Use the following equation :

[tex]\qquad \sf  \dashrightarrow \: gradient = \dfrac{y_2 - y_ 1}{x_2 - x_1} [/tex]

[tex]\qquad \sf  \dashrightarrow \: g = \dfrac{2 - ( - 1)}{0 - 1} [/tex]

[tex]\qquad \sf  \dashrightarrow \: g = \dfrac{2 + 1}{ - 1} [/tex]

[tex]\qquad \sf  \dashrightarrow \: g = - 3[/tex]

Hence, the gradient = -3 for the given line ~

Gradient means slope

Take 2 points

  • (2,-4)
  • (0,2)

Slope:-

[tex]\\ \rm\hookrightarrow m=\dfrac{2+4}{-2}[/tex]

[tex]\\ \rm\hookrightarrow m=-6/2[/tex]

[tex]\\ \rm\hookrightarrow m=-3[/tex]