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What is the missing constant term in the perfect square that starts with x2+10x

Sagot :

Answer:

+25

Step-by-step explanation:

(x+5)²=x²+10x+25

rayyan09
Find missing constant of quadratic equation:- X^2+10x+?
Solution:- since we know that,
(a+b)^2= a^2+2ab+b^2
Thus, by applying this formula in this equation(x^2+10x+?) we can find the missing constant
Like this:
(x)^2+2(x)(10)+? ——[2 is multiplied and due to the main formula: (a²+2ab+b²)]

(x)²+2(x)(10)(1/2)²+? ——-[we multiply half of 2 with square]

(x)²+2(x)(5)+?

As we know 5 in this equation is like b in main formula (mentioned above) therefore we write the missing constant (b)² as (5)²:-

(x)²+2(x)(5)+(5)²

Hence the missing constant is (5)².
By solving it further:
We use completing square method,

(x)²+2(x)(5)+(5)²=(x+5)²

Which is the required answer (in detail)

I hope you all got it…
Thanks
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