Answered

Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Our Q&A platform offers a seamless experience for finding reliable answers from experts in various disciplines. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

Mg + 2AgNO3 -> 2Ag + Mg(NO3)2

How many grams of magnesium (Mg) are needed to completely react with 3.00 moles of silver nitrate (AgNO3)?

A. 72.9g Mg
B. 255g Mg
C. 16.2g Mg
D. 36.5g Mg
E. 18.2g Mh

Sagot :

rspill6

Answer:

146 grams Mg

Explanation:

Mg + 2AgNO3 -> 2Ag + Mg(NO3)2

The balanced equation tells us we need 1 mole of Mg for every 2 moles of silver nitrate.

Since we have 3.00 moles of AgNO3, we'll need 2x that, or 6 moles of Mg.

The molar mass of Mg is 24.3 grams/mole

(6 moles Mg)(24.3 grams Mg/mole Mg) =  145.8 grams Mg.  146 grams with 3 sig figs.

Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.