Answer:
3.03L
Explanation:
Convert 6.1g of Sulfur to moles
Moles = mass ÷ molar mass
Molar mass of Sulfur = 32 g/mol
Moles = 6.1 ÷ 32 = 0.1906 mol
The overall equation between sulphur and oxygen to produce sulphur trioxide: multiply first equation by 2 and add both equations which cancels out SO2 in both equations to give:
2S + 3O2 ---> 2SO3
2 moles of S : 3 moles of O2
0.1906 mol : x mol
Cross multiply
3 × 0.1906 = 2x
0.5718 = 2x
x = 0.2859
moles of oxygen:
0.2859 mol
By ideal gas law:
PV =nRT
P (pressure) is in atm = 4.75
n = no of moles = 0.2859 mol
T is temperature in kelvin
Convert degrees to Kelvin + 273
340 + 273 = 613K
R which is gas constant is 0.0821 atm.L/Kmol
V= nRT/P
V = (0.2859 × 0.0821 × 613) ÷ (4.75) = 3.03L (3sf)
