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Find the volume for [tex]O_{2[/tex]

Find The Volume For TexO2tex class=

Sagot :

Answer:

3.03L

Explanation:

Convert 6.1g of Sulfur to moles

Moles = mass ÷ molar mass

Molar mass of Sulfur = 32 g/mol

Moles = 6.1 ÷ 32 = 0.1906 mol

The overall equation between sulphur and oxygen to produce sulphur trioxide: multiply first equation by 2 and add both equations which cancels out SO2 in both equations to give:

2S + 3O2 ---> 2SO3

2 moles of S : 3 moles of O2

0.1906 mol : x mol

Cross multiply

3 × 0.1906 = 2x

0.5718 = 2x

x = 0.2859

moles of oxygen:

0.2859 mol

By ideal gas law:

PV =nRT

P (pressure) is in atm = 4.75

n = no of moles = 0.2859 mol

T is temperature in kelvin

Convert degrees to Kelvin + 273

340 + 273 = 613K

R which is gas constant is 0.0821 atm.L/Kmol

V= nRT/P

V = (0.2859 × 0.0821 × 613) ÷ (4.75) = 3.03L (3sf)

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