catherizamorarivera
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Solve this please!! I'm really stuck

please answer with explanation, and correct answer.

Making this a ( 10 POINT) question I need help

Thanks, will be helpful if help is done!!
(ALGEBRA)

Solve This Please Im Really Stuckplease Answer With Explanation And Correct AnswerMaking This A 10 POINT Question I Need Help Thanks Will Be Helpful If Help Is class=

Sagot :

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Answer:

-74.

Step-by-step explanation:

First, notice that we can divide it into 2 equations (1 on each side of the equal symbol).

1st step:

Replace where's x by -2 in the left equation:

[tex]x+\:-4+\:-2(3x-5)=\square\mathrm{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:replace\:x\:by\:-2}\\-2+\:-4+\:-2((3\cdot-2)-5)=\square\mathrm{\:\:\:\:solve\:the\:multiplication}\\-2-4-2(-6-5)=\square\mathrm{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:remove\:excess\:symbols}\\-2-4-2(-11)=\square\mathrm{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:solve\:multiplication}\\-2-4+22=\square\mathrm{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:solve\:subtraction}\\16=\square[/tex]

2nd step:

Now, we will replace the squares with 16 in the second equation. Look:

[tex]\square +-4+-2(3\cdot\square\cdot-5)=\triangle\\16 +-4+-2(3\cdot16-5)\\16-4-2(48-5)\\16-4-2(43)\\16-4-86\\=-74[/tex]

So, the answer is -74.

We also can solve it in another way:

[tex]x-4-2(3x-5)=\\x-4-6x+10\\-5x+6\\\\\mathrm{let's\:replace\:x\:by\:-2:}\\-5\cdot(-2)+6\\10+6\\=16[/tex]

Now let's call the gray square as y in the second equation:

[tex]y-4-2(3y-5)\\y-4-6y+10\\-5y+6\\\\\mathrm{let's\:replace\:y\:by\:16:}\\-5\cdot(16)+6\\-80+6\\=-74[/tex]

So, your final answer is -74.

Hope it helps! :D

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