Answer:
-74.
Step-by-step explanation:
First, notice that we can divide it into 2 equations (1 on each side of the equal symbol).
1st step:
Replace where's x by -2 in the left equation:
[tex]x+\:-4+\:-2(3x-5)=\square\mathrm{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:replace\:x\:by\:-2}\\-2+\:-4+\:-2((3\cdot-2)-5)=\square\mathrm{\:\:\:\:solve\:the\:multiplication}\\-2-4-2(-6-5)=\square\mathrm{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:remove\:excess\:symbols}\\-2-4-2(-11)=\square\mathrm{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:solve\:multiplication}\\-2-4+22=\square\mathrm{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:solve\:subtraction}\\16=\square[/tex]
2nd step:
Now, we will replace the squares with 16 in the second equation. Look:
[tex]\square +-4+-2(3\cdot\square\cdot-5)=\triangle\\16 +-4+-2(3\cdot16-5)\\16-4-2(48-5)\\16-4-2(43)\\16-4-86\\=-74[/tex]
So, the answer is -74.
We also can solve it in another way:
[tex]x-4-2(3x-5)=\\x-4-6x+10\\-5x+6\\\\\mathrm{let's\:replace\:x\:by\:-2:}\\-5\cdot(-2)+6\\10+6\\=16[/tex]
Now let's call the gray square as y in the second equation:
[tex]y-4-2(3y-5)\\y-4-6y+10\\-5y+6\\\\\mathrm{let's\:replace\:y\:by\:16:}\\-5\cdot(16)+6\\-80+6\\=-74[/tex]
So, your final answer is -74.
Hope it helps! :D
