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Sagot :
Solution:
It should be noted:
- Opposite sides of a rhombus are always equal.
- Opposite angles of a rhombus are always equal.
Thus:
- (-y - 10) = 90°
- 3z - 3 = 90°
- 4x - 2 = 90°
Finding x:
- 4x - 2 = 90°
- => 4x = 90 + 2
- => 4x = 92
- => x = 23
Finding y:
- (-y - 10) = 90°
- => -y - 10 = 90°
- => -y = 100
- => y = -100
Finding z:
- 3z - 3 = 90°
- => 3z = 90 + 3
- => 3z = 93
- => z = 31
Opposite angles are equal
[tex]\\ \rm\hookrightarrow 90=-y-10[/tex]
[tex]\\ \rm\hookrightarrow -y=90+10[/tex]
[tex]\\ \rm\hookrightarrow y=-100[/tex]
And consecutive angles have some 180
- So all angles are of 90°
[tex]\\ \rm\hookrightarrow 3z-3=90[/tex]
[tex]\\ \rm\hookrightarrow 3z=93[/tex]
[tex]\\ \rm\hookrightarrow z=31[/tex]
And
[tex]\\ \rm\hookrightarrow 4x-2=90[/tex]
[tex]\\ \rm\hookrightarrow 4x=92[/tex]
[tex]\\ \rm\hookrightarrow 23[/tex]
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