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Find a linear function h, given h(3) = - 4 and h( - 2) = 16. Then find h(2).


Sagot :

express in coordinate pairs: (x,y)

h(3) = - 4 ⇒ 3,-4

h( - 2) = 16 ⇒ -2, 16

[tex]\tt slope=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{16-(-4)}{-2-3}=\dfrac{20}{-5}=-4[/tex]

equation:

[tex]\tt y-y_1=m(x-x_1)\rightarrow m=slope\\\\y+4=-4(x-3)\\\\y=-4x+8[/tex]

for h(2):

[tex]\tt y=-4(2)+8=0[/tex]

h(2) = 0