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What are the roots (solutions) of the polynomial equation:x^3-2x^2=15x

Sagot :

Answer:

x = 0, 5, -3

Step-by-step explanation:

You start by factoring [tex]x^3-2x^2=15x[/tex] which turns into [tex]x(x+3)(x-5)=0[/tex] from here, you set factors equal to 0.

x=0, x would be 0

(x+3)=0, x would be -3

(x−5)=0, x woud be 5