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QUESTION 2. What is the molar mass of a gas that takes three times longer to effuse than helium?​

Sagot :

Molecular weight of x=36g/mol
(According to graham's law of effusion or diffusion, the rate of effusion of a gas is inversely proportional to the square root of the mass of its particles.

RateB
RateA

=
(
molarmassA
molarmassB

)



Let Rate of unknown gas = x; Rate of Helium = 3x; mass of unknown gas = y
mass of He = 4.

x
3x

=
(
4
y





(
4
y

)

=3

squaring on both sides

(
4
y

)

=9

∴y=4×9=36u)
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