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Sagot :
Answer:
[tex]55[/tex] [tex]grames[/tex] [tex]02\times\left(1\ mol\ 02\div32\ g\ 02\right)\times\left(2\ mol\ H20\div1\ mol\ 02\right)\times\left(22.4\ L\div1\ mol\ H20\right)=77\ L\ HTO\left(g\right)[/tex]
Explanation:
It's about 62 milliliters in liquid form.
I hope this helps you
:)
1 mole of gas at STP = 22.4 L
Reaction:
2H₂(g) + O₂(g) → 2H₂O(l)
mole oxgen as a limiting reactant
mole oxygen: mass : molar mass = 55 g : 32 = 1.719
mole water H₂O based on mole oxygen as a limiting reactant
mole H₂O from reaction coefficient: 2/1 x mole O₂ = 2/1 x 1.719 = 3.438
liters H₂O at STP = 3.438 x 22.4 L = 77.0112 L
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