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An elephant weighs 40,000 newtons. Each of its four feet has an area of 500cm^2. Of the elephant stands on one foot, what pressure does it put on the ground?

Sagot :

VirαtKσhli

Answer:

[tex]\large\boxed{\sf Pressure = 3.2\times 10^6\ Pa }[/tex]

Explanation:

Here it is given that a elephant weighs 40,000 N and the area of its 4 feet is 500cm² . We need to find out what pressure will it exert if it stands on one foot .

Since area of 4 feet was 500cm² ,

Then the area of 1 foot will be 500cm²/4 = 125cm² .

Now , as we know that ;

[tex]\sf\qquad\longrightarrow \Bigg\lgroup Pressure =\dfrac{Force}{Area}\Bigg\rgroup\\\\ [/tex]

☯️ [tex]\underline{\underline{\boldsymbol{ On \ substituting \ the \ respective \ values \ }}}[/tex]

[tex]\sf\qquad\longrightarrow Pressure =\dfrac{Force}{Area}\\\\[/tex]

[tex]\sf\qquad\longrightarrow Pressure =\dfrac{40,000\ N }{125cm^2}\\\\[/tex]

[tex]\sf\qquad\longrightarrow Pressure =\dfrac{ 40,000\ N \times 10^4}{125m^2}\\\\[/tex]

[tex]\sf\qquad\longrightarrow \boxed{\pink{\frak{ Pressure = 3.2\times 10^6 \ Pascal }}} [/tex]

[tex]\rule{200}4[/tex]

Pressure :- Force/area

= 40000n/125cm²

=40000n×10⁴/125cm²

=3.2×10⁶ Pascal

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