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Sagot :
We know that,
[tex] \qquad{ \pmb{ \bf{{Total \: surface \: area}_{(cylinder)} = 2πr(h + r) }}}[/tex]
Now, Substituting the given values in the formula :
[tex]\qquad \sf \: { \dashrightarrow 2 × π × 2 (9 + 2) }[/tex]
[tex]\qquad \sf \: { \dashrightarrow 2 × π × 2 (11) }[/tex]
[tex]\qquad \sf \: { \dashrightarrow 2 × π × 22 }[/tex]
[tex]\qquad \sf \: { \dashrightarrow 44 π }[/tex]
[tex]\qquad \sf \: { \dashrightarrow 44 π } \: [/tex]
Since, value of pi is 3.14 approximately, therefore here we will take the value of pi as 3.14
[tex]\qquad \sf \: { \dashrightarrow 44 \times 3.14 } \: [/tex]
[tex]\qquad \sf \bf { \dashrightarrow 138.16 } \:[/tex]
Therefore,
- Surface area of cylinder is 138.16 cm²
The surface area of the cylinder with the given values of base radius and height is approximately 138.16 units².
What is a cylinder?
A cylinder is simply a 3-dimensional shape having two parallel circular bases joined by a curved surface.
The surface area of a cylinder is expressed as;
A = 2πrh + 2πr²
Where r is radius of the circular base, h is height and π is constant pi ( π = 3.14 )
Given the data in the question;
- Radius r = 2 units
- Height h = 9 units
- Surface area of the cylinder A = ?
We substitute our values into the expression above.
A = 2πrh + 2πr²
A = ( 2 × 3.14 × 2 units × 9 units ) + ( 2 × 3.14 × (2 unit)² )
A = ( 2 × 3.14 × 2 units × 9 units ) + ( 2 × 3.14 × 4 unit² )
A = 113.04 units² + 25.12 units²
A = 138.16 units²
Therefore, the surface area of the cylinder with the given values of base radius and height is approximately 138.16 units².
Learn more about cylinders here: brainly.com/question/16788902
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