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What is the surface area of a cylinder with base radius 2 and height 9
Either enter an exact answer in terms of T or use 3.14 for and enter your answer as a decimal.

Sagot :

We know that,

[tex] \qquad{ \pmb{ \bf{{Total \: surface \: area}_{(cylinder)} = 2πr(h + r) }}}[/tex]

Now, Substituting the given values in the formula :

[tex]\qquad \sf \: { \dashrightarrow 2 × π × 2 (9 + 2) }[/tex]

[tex]\qquad \sf \: { \dashrightarrow 2 × π × 2 (11) }[/tex]

[tex]\qquad \sf \: { \dashrightarrow 2 × π × 22 }[/tex]

[tex]\qquad \sf \: { \dashrightarrow 44 π }[/tex]

[tex]\qquad \sf \: { \dashrightarrow 44 π } \: [/tex]

Since, value of pi is 3.14 approximately, therefore here we will take the value of pi as 3.14

[tex]\qquad \sf \: { \dashrightarrow 44 \times 3.14 } \: [/tex]

[tex]\qquad \sf \bf { \dashrightarrow 138.16 } \:[/tex]

Therefore,

  • Surface area of cylinder is 138.16 cm²

nuhulawal20

The surface area of the cylinder with the given values of base radius and height is approximately 138.16 units².

What is a cylinder?

A cylinder is simply a 3-dimensional shape having two parallel circular bases joined by a curved surface.

The surface area of a cylinder is expressed as;

A = 2πrh + 2πr²

Where r is radius of the circular base, h is height and π is constant pi ( π = 3.14 )

Given the data in the question;

  • Radius r = 2 units
  • Height h = 9 units
  • Surface area of the cylinder A = ?

We substitute our values into the expression above.

A = 2πrh + 2πr²

A = ( 2 × 3.14 × 2 units × 9 units ) + ( 2 × 3.14 × (2 unit)² )

A = ( 2 × 3.14 × 2 units × 9 units ) + ( 2 × 3.14 × 4 unit² )

A = 113.04 units² + 25.12 units²

A = 138.16 units²

Therefore, the surface area of the cylinder with the given values of base radius and height is approximately 138.16 units².

Learn more about cylinders here: brainly.com/question/16788902

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