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a)
2 3 3 2 1 A : 3
5 5 5 3 2
  
       
b)
5 1 7 B 2 :1
6 5 12
  
      
c)
3 4 3 C 15 3 8
13 7 13
 
      
d)
13 1 1 11 D 15 6 :11 2 :1
18 27 8 40
 
      
e) E = (-3,2).
15 4 2 0,8 2 :3
64 15 3
  
     

f)
7 4 7 7 7 F . . 5
9 11 9 11 9
 
  
g) G = 50% .
1 7 1 .10. .0,75
3 35

h)
 
 
2 3
2 1 2 I 5 4,5 2
5 2 4
 
        

 
2 3 5 2
k)K 0,25: . 2
3 4 8
   

 
2 2
3
2
o
1 1 1 4 1 3 1 1 4 5 5 l) N : 2 m)M 6 2 .3 1 : n)O 2 . 1 :
2 4 2 5 8 8 4 4 3 6 12
1 1 1 1 1 5 p)P 3 2 : 4 5 2 q)Q 125%. : 1 1,5 2002
3 4 6 4 2 16
        
                          
       
                        

s) (-5,6).(-42,2) + (-57,8). (-5,6) t) (2,6.3 – 2,6.5): (0,121 + 1,879)