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[tex]x \: varies \: as \: product \: u \: v \: and \: inversely \\ as \: their \: sum \: if \: x - 3 \: when \: u = 3 \: \\ and \: v = 1 \: what \: is \: the \: value \: of \: x \: if \\ u = 3 \: and \: v = 3[/tex]
Pls help me with this​

Sagot :

[Note that you don't have to evaluate k to solve the problem]

[tex]x = \frac{kuv}{(u+v)}[/tex]

That means that

[tex]x \frac{(u+v)}{(uv)} = k, a \: constant[/tex]

So, you want [tex]x[/tex]such that

[tex]x \frac{(3+3)}{(3 \times 3)} = 3 \frac{(3+1)}{(3 \times 1)}[/tex]

[tex]x=6[/tex]