Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Join our Q&A platform to get precise answers from experts in diverse fields and enhance your understanding. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
- AC=Hypotenuse=20
- BC=Base=16
AB:-
Apply Pythagorean theorem
[tex]\\ \rm\rightarrowtail P^2=H^2-B^2[/tex]
[tex]\\ \rm\rightarrowtail P^2=20^2-16^2[/tex]
[tex]\\ \rm\rightarrowtail P^2=400-256[/tex]
[tex]\\ \rm\rightarrowtail P^2=144[/tex]
[tex]\\ \rm\rightarrowtail AB=12[/tex]
Now
- DE=AB/3=12/3=4
- EF=BC/3=16/3=5.3
- DF=AC/3=20/3=6.6
Now
[tex]\\ \rm\rightarrowtail sinF=\dfrac{DE}{DF}[/tex]
[tex]\\ \rm\rightarrowtail sinF=\dfrac{4}{6.6}[/tex]
[tex]\\ \rm\rightarrowtail sinF=0.61[/tex]


Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.