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a vertical pole cast a shadow of 20m long when the altitude of the sun is 60°what is the height of the pole?​

Sagot :

Answer:

20√3

Step-by-step explanation:

20 x tan(60°)

=

20√3

[tex]\tt Tg~\alpha =\dfrac{height~of~the~pole}{shadow}\\\\height=Tg~60\times 20=34.64~m[/tex]

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