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Find equation of a line passing through the points
(0, 2) and (6, 20)


Sagot :

Step-by-step explanation:

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[tex]\tt slope=m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

[tex]\tt =\dfrac{20-2}{6-0}=3[/tex]

equation:

y-y₁ = m(x-x₁), for point (0,2)

y-2 = 3(x-0)

y-2 = 3x

y = 3x+2